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12x^2=19x*10
We move all terms to the left:
12x^2-(19x*10)=0
We add all the numbers together, and all the variables
12x^2-(+19x*10)=0
We get rid of parentheses
12x^2-19x*10=0
Wy multiply elements
12x^2-190x=0
a = 12; b = -190; c = 0;
Δ = b2-4ac
Δ = -1902-4·12·0
Δ = 36100
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{36100}=190$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-190)-190}{2*12}=\frac{0}{24} =0 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-190)+190}{2*12}=\frac{380}{24} =15+5/6 $
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